# 832. Flipping an Image

Given a binary matrix `A`, we want to flip the image horizontally, then invert it, and return the resulting image.

To flip an image horizontally means that each row of the image is reversed.  For example, flipping `[1, 1, 0]` horizontally results in `[0, 1, 1]`.

To invert an image means that each `0` is replaced by `1`, and each `1` is replaced by `0`. For example, inverting `[0, 1, 1]` results in `[1, 0, 0]`.

Example 1:

``````Input: [[1,1,0],[1,0,1],[0,0,0]]
Output: [[1,0,0],[0,1,0],[1,1,1]]
Explanation: First reverse each row: [[0,1,1],[1,0,1],[0,0,0]].
Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]
``````

Example 2:

``````Input: [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
Output: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
Explanation: First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]].
Then invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
``````

Notes:

• `1 <= A.length = A[0].length <= 20`
• `0 <= A[i][j] <= 1`

``````class Solution {
public:
vector<vector<int>> flipAndInvertImage(vector<vector<int>>& A) {
for (auto &row : A) reverse(row.begin(), row.end());
for (auto &row : A) {
for (int &num : row) num ^= 1;
}
return A;
}
};
``````

``````class Solution {
public:
vector<vector<int>> flipAndInvertImage(vector<vector<int>>& A) {
vector<vector<int>> res(A.size());
for (int i = 0; i < A.size(); ++i) {
for (int j = (int)A[i].size() - 1; j >= 0; --j) {
res[i].push_back(!A[i][j]);
}
}
return res;
}
};
``````

https://leetcode.com/problems/flipping-an-image/

https://leetcode.com/problems/flipping-an-image/discuss/130590/C%2B%2BJavaPython-Reverse-and-Toggle

LeetCode All in One 题目讲解汇总(持续更新中…)

 微信打赏 Venmo 打赏
（欢迎加入博主的知识星球，博主将及时答疑解惑，并分享刷题经验与总结，试运营期间前五十位可享受半价优惠～）

×

Help us with donation