# 81. Search in Rotated Sorted Array II

Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.

(i.e., `[0,0,1,2,2,5,6]` might become `[2,5,6,0,0,1,2]`).

You are given a target value to search. If found in the array return `true`, otherwise return `false`.

Example 1:

``````Input: nums = [2,5,6,0,0,1,2], target = 0
Output: true
``````

Example 2:

``````Input: nums = [2,5,6,0,0,1,2], target = 3
Output: false
``````

• This is a follow up problem to Search in Rotated Sorted Array, where `nums` may contain duplicates.
• Would this affect the run-time complexity? How and why?

``````class Solution {
public:
bool search(vector<int>& nums, int target) {
int n = nums.size(), left = 0, right = n - 1;
while (left <= right) {
int mid = (left + right) / 2;
if (nums[mid] == target) return true;
if (nums[mid] < nums[right]) {
if (nums[mid] < target && nums[right] >= target) left = mid + 1;
else right = mid - 1;
} else if (nums[mid] > nums[right]){
if (nums[left] <= target && nums[mid] > target) right = mid - 1;
else left = mid + 1;
} else --right;
}
return false;
}
};
``````

Github 同步地址：

https://github.com/grandyang/leetcode/issues/81

Search in Rotated Sorted Array

https://leetcode.com/problems/search-in-rotated-sorted-array-ii/

https://leetcode.com/problems/search-in-rotated-sorted-array-ii/discuss/28194/C%2B%2B-concise-log(n)-solution

https://leetcode.com/problems/search-in-rotated-sorted-array-ii/discuss/28218/My-8ms-C%2B%2B-solution-(o(logn)-on-average-o(n)-worst-case)

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