205. Isomorphic Strings

 

Given two strings  s  and  t , determine if they are isomorphic.

Two strings are isomorphic if the characters in  s  can be replaced to get  t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

Example 1:

Input: _s_ = "egg", _t =_"add"
Output: true

Example 2:

Input: _s_ = "foo", _t =_"bar"
Output: false

Example 3:

Input: _s_ = "paper", _t =_"title"
Output: true

Note:
You may assume both  s and  t have the same length.

  

这道题让我们求同构字符串,就是说原字符串中的每个字符可由另外一个字符替代,可以被其本身替代,相同的字符一定要被同一个字符替代,且一个字符不能被多个字符替代,即不能出现一对多的映射。根据一对一映射的特点,需要用两个 HashMap 分别来记录原字符串和目标字符串中字符出现情况,由于 ASCII 码只有 256 个字符,所以可以用一个 256 大小的数组来代替 HashMap,并初始化为0,遍历原字符串,分别从源字符串和目标字符串取出一个字符,然后分别在两个数组中查找其值,若不相等,则返回 false,若相等,将其值更新为 i + 1,因为默认的值是0,所以更新值为 i + 1,这样当 i=0 时,则映射为1,如果不加1的话,那么就无法区分是否更新了,代码如下:

 

class Solution {
public:
    bool isIsomorphic(string s, string t) {
        int m1[256] = {0}, m2[256] = {0}, n = s.size();
        for (int i = 0; i < n; ++i) {
            if (m1[s[i]] != m2[t[i]]) return false;
            m1[s[i]] = i + 1;
            m2[t[i]] = i + 1;
        }
        return true;
    }
};

 

Github 同步地址:

https://github.com/grandyang/leetcode/issues/205

 

类似题目:

Word Pattern

 

参考资料:

https://leetcode.com/problems/isomorphic-strings/

https://leetcode.com/problems/isomorphic-strings/discuss/57796/My-6-lines-solution

https://leetcode.com/problems/isomorphic-strings/discuss/57810/Short-Java-solution-without-maps

 

LeetCode All in One 题目讲解汇总(持续更新中…)


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