# 35. Search Insert Position

Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You must write an algorithm with `O(log n)` runtime complexity.

Example 1:

``````**Input:** nums = [1,3,5,6], target = 5
**Output:** 2
``````

Example 2:

``````**Input:** nums = [1,3,5,6], target = 2
**Output:** 1
``````

Example 3:

``````**Input:** nums = [1,3,5,6], target = 7
**Output:** 4
``````

Constraints:

• `1 <= nums.length <= 10^4`
• `-10^4 <= nums[i] <= 10^4`
• `nums` contains distinct values sorted in ascending order.
• `-10^4 <= target <= 10^4`

``````class Solution {
public:
int searchInsert(vector<int>& nums, int target) {
for (int i = 0; i < nums.size(); ++i) {
if (nums[i] >= target) return i;
}
return nums.size();
}
};
``````

``````class Solution {
public:
int searchInsert(vector<int>& nums, int target) {
if (nums.back() < target) return nums.size();
int left = 0, right = nums.size();
while (left < right) {
int mid = left + (right - left) / 2;
if (nums[mid] < target) left = mid + 1;
else right = mid;
}
return right;
}
};
``````

Github 同步地址：

https://github.com/grandyang/leetcode/issues/35

https://leetcode.com/problems/search-insert-position/

https://leetcode.com/problems/search-insert-position/discuss/15372/Simple-Java-solution

https://leetcode.com/problems/search-insert-position/discuss/15080/My-8-line-Java-solution

LeetCode All in One 题目讲解汇总(持续更新中…)

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