1352. Product of the Last K Numbers

 

Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment.

Design an algorithm to serialize and deserialize a binary search tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary search tree can be serialized to a string and this string can be deserialized to the original tree structure.

The encoded string should be as compact as possible.

Note: Do not use class member/global/static variables to store states. Your serialize and deserialize algorithms should be stateless.

 

这道题让我们对二叉搜索树序列化和去序列化，跟之前那道Serialize and Deserialize Binary Tree极其相似，虽然题目中说编码成的字符串要尽可能的紧凑，但是我们并没有发现跟之前那题有何不同，而且也没有看到能够利用BST性质的方法，姑且就按照之前题目的解法来写吧：

 

解法一：

class Codec {
public:

    // Encodes a tree to a single string.
    string serialize(TreeNode* root) {
         ostringstream os;
         serialize(root, os);
         return os.str();
    }

    // Decodes your encoded data to tree.
    TreeNode* deserialize(string data) {
        istringstream is(data);
        return deserialize(is);
    }
    
    void serialize(TreeNode* root, ostringstream& os) {
        if (!root) os << "# ";
        else {
            os << root->val << " ";
            serialize(root->left, os);
            serialize(root->right, os);
        }
    }
    
    TreeNode* deserialize(istringstream& is) {
        string val = "";
        is >> val;
        if (val == "#") return NULL;
        TreeNode* node = new TreeNode(stoi(val));
        node->left = deserialize(is);
        node->right = deserialize(is);
        return node;
    }
};

 

另一种方法是层序遍历的非递归解法，这种方法略微复杂一些，我们需要借助queue来做，本质是BFS算法，也不是很难理解，就是BFS算法的常规套路稍作修改即可，参见代码如下：

 

解法二：

class Codec {
public:

    // Encodes a tree to a single string.
    string serialize(TreeNode* root) {
        if (!root) return "";
        ostringstream os;
        queue<TreeNode*> q;
        q.push(root);
        while (!q.empty()) {
            TreeNode *t = q.front(); q.pop();
            if (t) {
            os << t->val << " ";
            q.push(t->left);
            q.push(t->right);
            } else {
                os << "# ";
            }
        }
        return os.str();
    }

    // Decodes your encoded data to tree.
    TreeNode* deserialize(string data) {
        if (data.empty()) return NULL;
        istringstream is(data);
        queue<TreeNode*> q;
        string val = "";
        is >> val;
        TreeNode *res = new TreeNode(stoi(val)), *cur = res;
        q.push(cur);
        while (!q.empty()) {
            TreeNode *t = q.front(); q.pop();
            if (!(is >> val)) break;
            if (val != "#") {
                cur = new TreeNode(stoi(val));
                q.push(cur);
                t->left = cur;
            }
            if (!(is >> val)) break;
            if (val != "#") {
                cur = new TreeNode(stoi(val));
                q.push(cur);
                t->right = cur;
            }
        }
        return res;
    }
};

 

类似题目：

Serialize and Deserialize Binary Tree

Find Duplicate Subtrees

Serialize and Deserialize N-ary Tree

 

参考资料：

https://leetcode.com/problems/serialize-and-deserialize-bst

https://leetcode.com/problems/serialize-and-deserialize-bst/discuss/93260/easy-bfs-java

 

LeetCode All in One 题目讲解汇总(持续更新中…)

---

转载请注明来源于 Grandyang 的博客 (grandyang.com)，欢迎对文章中的引用来源进行考证，欢迎指出任何有错误或不够清晰的表达。可以在下面评论区评论，也可以邮件至 grandyang@qq.com